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The solutions for the equation,
3x^2+7x+4=0 are -1 and -4/3.

So, the answer choices are C and D
User Armand Grillet
by
7.7k points
2 votes
We have the following equation:
3x2 + 7x + 4 = 0
Using the resolver we have:
x = (- b +/- root (b2 - 4ac)) / 2a
Substituting values we have:
x = (- (7) +/- root ((7) 2 - 4 (3) (4))) / 2 (3)
Rewriting:
x = (- 7 +/- root (49 - 48)) / 6
x = (- 7 +/- root (1)) / 6
x = (- 7 +/- 1) / 6
The results are:
x = (- 7 + 1) / 6 = -6/6 = -1
x = (- 7 - 1) / 6 = -8 / 6 = -4/3
Answer:
x = -1
x = -4/3
option C and D
User Mostafa Shahverdy
by
8.2k points

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