Question

Hey can you please help me posted picture of question

Answer 1

The equation is: x2-5x + 1 = 0 Here we can say that this is a quadratic equation so we must find x using the formula of a quadratic equation which is: x = (- b +/- root (b2 - 4ac)) / 2a Substitute the values : x = (- (- 5) +/- root ((- 5) 2 - 4 (1) (1))) / 2 (1) x = (5 +/- root (25 - 4)) / 2 x = (5 +/- root (21)) / 2 Which is equal to= x = (5 + root (21)) / 2 x = (5 - root (21)) / 2 So the answers would be D and E

Answer 2

We have the following equation:
x2-5x + 1 = 0
Using the resolver we have:
x = (- b +/- root (b2 - 4ac)) / 2a
Substituting values we have:
x = (- (- 5) +/- root ((- 5) 2 - 4 (1) (1))) / 2 (1)
Rewriting:
x = (5 +/- root (25 - 4)) / 2
x = (5 +/- root (21)) / 2
The results are:
x = (5 + root (21)) / 2
x = (5 - root (21)) / 2
Answer:
x = (5 + root (21)) / 2
x = (5 - root (21)) / 2
option D and E