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Two ships leave a harbor together traveling on courses that have an angle of 125° between them. if they each travel 501 miles, how far apart are they (to the nearest mile)?
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Two ships leave a harbor together traveling on courses that have an angle of 125° between them. if they each travel 501 miles, how far apart are they (to the nearest mile)?

User Bustawin
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1 Answer

2 votes
Answer: 889 miles


Step-by-step explanation:

Cosine Rule : a² = b² + c² - 2bcCosA

a² = 501² + 501² - 2(501)(501)Cos(125)

a² = 789 938

a = √789 938

a = 889 miles
User Mariaelena
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