Question

Write the formula of a coordination compound made of two complex ions: one a complex of v(iii) with two ethylenediamine molecules and two cl− ions as ligands and the other a complex of ni(ii) having a coordination number of 4 with cl− ions as ligands.

Answer 1

The answer is: " [V₍en₎₂Cl₂]₂ [NiCl₄] " .
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Step-by-step explanation:
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Note that: [V³⁺ ₍en₎₂ (Cl⁻)²] is a "+1" charged cation; and that:+1 ion

[Ni²⁺ (Cl⁻)₄ is a "-2" charged anion;

As such: the chemical formula for the compound is written as:
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→ "[V₍en₎₂Cl₂]₂ [NiCl₄] ;
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The answer is: " [V₍en₎₂Cl₂]₂ [NiCl₄] " .
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