Question

A wheel starts from rest and rotates with constant angular acceleration to reach an angular speed of 11.1 rad/s in 2.99 s.(a) find the magnitude of the angular acceleration of the wheel.

Answer 1

The angular acceleration of a rotating object is given by

`\alpha = (\omega_f - \omega_i)/(\Delta t)`
where

`\omega_f` is the final angular speed of the object

`\omega_i` is its initial angular speed

`\Delta t` is the time taken to accelerate

For the wheel in our problem,
`\omega_f=11.1 rad/s`,
`\omega_i = 0` and
`\Delta t=2.99 s`, so its angular acceleration is

`\alpha= (11.1 rad/s-0)/(2.99 s)=3.71 rad/s^2`