26.8k views
2 votes
The graphs of the equations y=2x+2 and y=-2x+a+1 intersect n quadrant 1 for which values of a?

○0 <a <1
○a <1
○a_>1
○a>1

User Walk
by
8.5k points

1 Answer

0 votes
Solve the system of equations:
y=2x+2 ................(1)
y=-2x+a+1............(2)
for x and y
(1)-(2)
4x-a+1=0 => x=(a-1)/4
(1)+(2)
2y=a+3 => y=(a+3)/2

x>0 if (a-1)/4>0 => a>1
y>0 if (a+3)/2>0 => a>-3

For both x & y >0, we have the condition a>1.

Note that if a=1, then the intersection poin lies ON the x-axis, and therefore NOT in quadrant 1.

User Mistaecko
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories