What is the solution set for square root of 3y+4=5 √(3y ) + 4 = 5

Question

What is the solution set for square root of 3y+4=5

`√(3y ) + 4 = 5`

Answer 1

We can solve it algebraically:

`√(3y) +4-4=5-4` (subtract 4 from both sides to isolate
`√(3y)`

`( √(3y))^(2) = (1)^(2)` (square both sides to get rid of square root on left side

`3y/3=1/3` (divide both sides by 3 to isolate y)

`y= (1)/(3)`