201k views
1 vote
Hey can you please help me posted picture of question :)

Hey can you please help me posted picture of question :)-example-1
User Ugoren
by
6.9k points

2 Answers

2 votes
The solutions of the equation in the given problem are C & D
User Ncrocfer
by
7.2k points
5 votes
Answer:
Correct options are C and D

Step-by-step explanation:
First we would need to expand the bracket on the left and then put the equation in standard form which is as follows:
ax² + bx + c = 0

This can be done as follows:
(2x+3)² = 10
(2x)² + 2(2x)(3) + (3)² = 10
4x² + 12x + 9 - 10 = 0
4x² + 12x - 1 = 0

By comparison, we would find that:
a = 4
b = 12
c = -1

Now, to get the roots, we would need to use the quadratic formula shown in the attached image

By substitution we would find that:
either x =
(-12+ √((12)^2-4(4)(-1)) )/(2(4)) = ( √(10) - 3 )/(2)

or x =
(-12- √((12)^2-4(4)(-1)) )/(2(4)) = (- √(10) - 3 )/(2)

Hope this helps :)
Hey can you please help me posted picture of question :)-example-1
User Kasper Munck
by
6.5k points