Answer:
Sodium Bicarbonate on decomposition produces Carbon dioxide gas and Water vapors.
2 NaHCO₂ → Na₂CO₃ (s) + CO₂ (g) + H₂O (g)
Step-by-step explanation:
Let suppose you burn 168 g ( 2 moles ) of NaHCO₃, a gas will produced and product is left behind. On measuring the product formed it will be almost equal to 105 g. This shows that the product is Na₂CO₃ and 1 mole of it is being produced after decomposition of sodium bicarbonate.