Question

Enter the y coordinate of the solution to this system of equations -2x+3y=-6. 5x-6y=15

Answer 1

did u want elimination method? if so I got (3,0)

Answer 2

The equations given to us are:

`-2x+3y=-6`.........(Equation 1)

and
`5x-6y=15`...(Equation 2)

Let us now isolate x in (Equation 1) by 3y from both sides and dividing by -2. We will get:

`x=(6+3y)/(2)`......(Equation 3)

Likewise, in order to isolate x in (Equation 2), we will have to add 6y to both sides and divide by 5. We will get:

`x=(15+6y)/(5)`.....(Equation 4)

Equating the right sides of both the equations 3 and 4 we get:

`(6+3y)/(2)=(15+6y)/(5)`

Cross-multiplication will give us:

`30+15y=30+12y`

Cancelling 30 from both sides will give us:

`15y=12y`

Subtracting 12y from both sides we get:

`15y-12y=3y=0`

Thus,
`y=0`

This is the required y coordinate of the solution to this system of equations.

Thus, y=0 is the answer.