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19 votes
19 votes
Please help me with HW

17x = 23
Make x the subject​

User Danilo Fuchs
by
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2 Answers

12 votes
12 votes
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User Gotmike
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23 votes
23 votes

Answer:


\boxed{x \approx1.4}

OR


\boxed{\tt x \approx \cfrac{23}{17}}

Explanation:


\bf \: Given \: equation :


17x = 23

Make x the subject means we need to find the value of x.


\bf \: Solution:


\tt \implies \: 17x = 23

Divide each side by 17 :


\tt \implies \cfrac{17x}{17} = \cfrac{23}{17}


\rm \: Firstly, cancel \: the \: LHS :

  • Cancel 17 ( which is on the numerator ) and cancel 17 ( which is on the denominator ) :-


\tt \implies \cfrac{ \cancel{17}x}{ \cancel{17}} = \cfrac{23}{17}

  • Results to,


\tt \implies \: \cfrac{1x}{1} = \cfrac{23}{17}


\tt \implies1x = \cfrac{23}{17}


\tt \implies{x} = \cfrac{23}{17}


\rm \: 23\; and \; 17 \: can't \: be \: cancelled .

But, We can convert 23/17 into decimal form.

That is,


\tt \implies \: x = 23 / 17


\tt \implies{x} = 1.352


\tt \implies{x} \approx1.4

Hence, the value of x would be 23/17 or 1.4 .


\rule{225pt}{2pt}

I hope this helps!

Let me know if you have any questions.

:D

User Tosin
by
3.2k points