230k views
5 votes
A ball is dropped from a height of 64 feet. Its height, in feet, can be modeled by the function h(t) = -16t square + 64, where t is the time in seconds since the ball was dropped. After how many seconds will the ball hit the ground?

User Mattis Asp
by
7.6k points

1 Answer

2 votes
t has to be bigger than 0
the ball hit the ground so h(t) =0
-16t^(2) +64 = 0 -> 16t^2= 64 -> t^2 = 4 -> t = 2s
User Kuldeep Dubey
by
8.8k points

No related questions found