Question

What is the discontinuity and zero of the function

Answer 1

The discontinuity are the point wherein the function is not defined.
The zeros are the points wherein f(x)=0.
Computing the discontinuity points:
Set
`x-1=0` then the discontinuity point is at
`x=1`.
Comptine the zeroes:
Set
`3x^2+x-4=0`
Compute the discriminant:
`1^2-4(3)(-4)=49=7^2.`
Then with quadratic formula we get the solutions:

`(-1-7)/6=-8/6\\(-1+7)/6=1`
The two zeros are
`(-8)/(6),1`