Question

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.

Find the lateral area for the regular pyramid.



L. A. =

Answer 1

4 square root 10

Explanation:

do pythagorean theorem = 1 squared + 3 squared = x squared

1+9=x squared = 10= x squared

take square root of both sides to get rid of one over x = square root of 10 the do formula to find 1 later face (1/2)(s)(l) = (1/2)(base side)(slant height)

(1/2)(2)(square root of 10) = square root of 10

times by 4 because 4 sides = 4 square root 10

Answer 2

The lateral area is 4√10 or 12.6.

We first find the slant height, s, using the Pythagorean theorem:
1²+3²=s²
1+9=s²
10=s²

Take the square root of each side:
√10=√s²
√10 = s

To find the area of one lateral face, we use the formula A=1/2bh:
A=1/2(2)(√10)=√10

There are 4 lateral faces, so the area is 4√10. Evaluated, this is 12.6.