Question

A die is thrown twice. What is the probability that: 1.Neither a multiple of 2 on the first throw nor a total of 6 will appear?2.Neither a doublet ordered pair nor a total of 10 will appear? Neither a multiple of 2 on the first throw nor a total of 6 will appear?

Answer 1

Neither a multiple of 2 on the first throw nor a total of 6 will appear? = 5/12

Neither a doublet ordered pair nor a total of 10 will appear? = 7/9

Step-by-step explanation:

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Answer 2

Neither a multiple of 2 on the first throw nor a total of 6 will appear is 7/9.
Neither a doublet ordered pair nor a total of 10 will appear is 5/12.
Hope this helps Bud.