Question

If f(4) = 246.4 when r = 0.04 for the function f(t) = Pe^rt , then what is the approximate value of P?

Answer 1

If f(4) = 246.4 when r = 0.04 for the function f(t) = Pe^rt , then what is the approximate value of P?
Solution:
f(t)=Pe^rt
when r=0.04, the f(t)=246.4, thus the value of P will be:
246.4=Pe^0.04t
P=(246.4)/(0.04t)
where t=time

Answer 2

209.96

Explanation:

The given function is
`f(t)=Pe^(rt)`

Given that f(4) = 246.4 when r = 0.04. Thus, we have

`f(4)=Pe^(r(4))\\\\246.4=Pe^(0.04\cdot4)`

Simplifying the exponent

`246.4=Pe^(0.16)`

Now, divide both sides by
`e^(0.16)`

`(246.4)/(e^(0.16))=P\\\\P=209.97`

Hence, the approximate value of P is 209.96