Question

1) A thin converging lens of focal length 11.9 cm

forms an image of an object placed 27.7 cm
from the lens.
Find the image distance.
Answer in units of cm.
2) What is the magnification for an object dis-
tance of 27.7 cm?
3) Find the location of the image for an object
distance of 4.46 cm.
Answer in units of cm.
4) Calculate the magnification for an object dis-
tance of 4.46 cm.

Answer 1

Step-by-step explanation:

Focal length

f

=

10.8

c

m

Object distance

d

o

=

35.7

c

m

Part A:

The image distance would be

1

f

=

1

d

o

+

1

d

i

1

10.8

c

m

=

1

35.7

c

m

+

1

d

i

d

i

≈

15.5

c

m

Part B:

The magnification would be

m

=

−

d

i

d

o

=

−

15.5

c

m

35.7

c

m

≈

−

0.43

Part C:

The image distance if the object distance

d

o

=

5.59

c

m

, would be

1

f

=

1

d

o

+

1

d

i

1

10.8

c

m

=

1

5.59

c

m

+

1

d

i

d

i

≈

−

11.6

c

m

Part D:

Its magnification would be

m

=

−

d

i

d

o

=

−

−

11.6

c

m

5.59

c

m

≈

2.08