Question

Molly wishes to make a lawn ornament in the form of a solid sphere. the clay being used to make the sphere weighs .075 pound per cubic inch. if the sphere's radius is 4 inches, what is the weight of the sphere, to the nearest pound?

Answer 1

To find the weight of the sphere, multiply its volume by the weight of the clay per cubic inch. Using the formula for the volume of a sphere, the weight is approximately 20 pounds.

Step-by-step explanation:

To calculate the weight of the sphere, we need to find its volume first. The formula for the volume of a sphere is V = (4/3)πr^3, where r is the radius. Plugging in the value of r = 4 inches, we get V = (4/3)π(4^3) = 268.082 cubic inches.

Next, we multiply the volume by the weight of the clay per cubic inch, which is 0.075 pounds. so the weight of the sphere is 268.082 * 0.075 = 20.10615 pounds.

Rounding to the nearest pound, the weight of the sphere is approximately 20 pounds.

Answer 2

The first thing we must do for this case is find the volume of the sphere.
The volume is given by:
V = (4/3) * (pi) * (r ^ 3)
Where,
A: Radius of the sphere
Substituting values:
V = (4/3) * (3.14) * (4 ^ 3)
V = 267.95 in ^ 3
Then, the weight of the sphere is:
W = (267.95) * (0.75)
W = 200.9625 pounds
Round to the nearest pound:
W = 201 pounds
Answer:
The weight of the sphere is:
W = 201 pounds