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How much heat is required to increase the temperature of 35.0 grams of water from 10.0°C to 45.0°C? (The specific heat of water is 4.18 J/g°C)
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How much heat is required to increase the temperature of 35.0 grams of water from 10.0°C to 45.0°C? (The specific heat of water is 4.18 J/g°C)

User Sandeep Fatangare
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2 Answers

4 votes
the correct answer is 5,120
User Ali Yousuf
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8.1k points
0 votes
Q = mCΔT
Q is heat in Joules, m is mass, C is the specific heat of water, delta T is the change in temperature

Q = (35g)(4.18)(35 degrees) = 5121 Joules or 5.12 kJ required


User Cgsd
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