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What is the ph of a solution that is 0.50 m in propanoic acid and 0.40 m in sodium propanoate. (ka for propanoic acid = 1.3 x 10-5)?
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What is the ph of a solution that is 0.50 m in propanoic acid and 0.40 m in sodium propanoate. (ka for propanoic acid = 1.3 x 10-5)?

User Vladislav Kievski
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1 Answer

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The pH is given by the Henderson - Hasselbalch equation:
pH = pKa + log([A-]/[HA])
pH = -log(1.3 x 10^-5) + log(0.50/0.40)
pH = 4.98
The answer to this question is 4.98.
User Gergonzalez
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