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Find a general term a(n) for the geometric sequence: a(3)=2, a(6)=1/4
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Jan 21, 2019
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Find a general term a(n) for the geometric sequence: a(3)=2, a(6)=1/4
Mathematics
middle-school
Parijat Kalia
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a_n=arⁿ⁻¹
a_n nth term sequence
a= first term of the sequence
r= common ratio
a₃=ar²
2=ar²
a₆=ar⁵
1/4=ar⁶
a=2/r²
1/4=r⁶/r²
1/4=r⁴
r=1/(4)^(1/4)
a=1/r²=1/(1/(4)^(1/4))^(2)=1/1/2= 2
a_n=2{1/(4)^(1/4)}ⁿ⁻¹
Pjcard
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Jan 27, 2019
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