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What mass of water must be used to make a 1.35 m solution that contains 8.20 mol NaOH?
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What mass of water must be used to make a 1.35 m solution that contains 8.20 mol NaOH?

User KingFeming
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Answer is: mass of water is 6.07 kilograms.
b(NaOH) = 1.35 m.
n(NaOH) = 8.20 mol.
b(NaOH) = n(NaOH) ÷ m(H₂O).
m(H₂O) = n(NaOH) ÷ b(NaOH).
m(H₂O) = 8.20 mol ÷ 1.35 mol/lg.
mm(H₂O) = 6.07 kg.
m - molality.
n - amount of substance.
User Axnsan
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