Question

How many moles of al2o3 are formed when 0.78 mol o2 reacts with aluminum?

Answer 1

Answer: The number of moles of
`Al_2O_3` produced will be 0.52 moles.

Step-by-step explanation:

The chemical equation for the production of aluminium oxide form aluminium and oxygen follows the equation:

`4Al+3O_2\rightarrow 2Al_2O_3`

By stoichiometry of the reaction:

3 moles of oxygen gas produces 2 moles of aluminium oxide.

So, 0.78 moles of oxygen gas will produce =
`(2)/(3)* 0.78=0.52` moles of aluminium oxide

Hence, the number of moles of
`Al_2O_3` produced will be 0.52 moles.

Answer 2

The balanced chemical equation is:
4 Al + 3 O₂ → 2 Al₂O₃
3 moles of oxygen ---gives--> 2 moles of Al₂O₃
0.78 mol of O₂ ---gives---> ? moles of Al₂O₃
So the number of moles of Al₂O₃ = (0.78 x 2) / 3 =0.52 mole