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A 20.0 kg object is at rest, and then speeds up to 16.0 m/s. How much work was done on this system?

A 20.0 kg object is at rest, and then speeds up to 16.0 m/s. How much work was done on this system?
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A 20.0 kg object is at rest, and then speeds up to 16.0 m/s. How much work was done on this system?

User Urfusion
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1 Answer

2 votes
Work=Change in Kinetic Energy
1/2mVf^2-1/2Vi^2=W
1/2(20)(16)^2-1/2(20)(0)^2=W
2560-0=W
W=2560J


User Brian Ensink
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7.1k points
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