Question

Which technique is most appropriate to use to solve each equation?

Drag the name of the technique into the box to match each equation

Answer 1

Explanation:

(A) The given equation is:

`(x+3)(x+2)=0`

The above equation can be solved using the zero product property which states that if
`ab=0`, then either
`a=0` or
`b=0` or both can be equal to zero, therefore the solution of the above equation will be:

`x=-3` or
`x=-2`.

(B) The given equation is:

`x^2+6=31`

The above equation can be solved using the square root property which states that we isolate the
`x^2` term and take the square root of the number on the other side of the equals sign, therefore the solution of the above equation will be:

`x^2=31-6`

`x^2=25`

`x={\pm}5`.

Answer 2

(x+3)(x+2)=0 zero product property
x^2+6=31 square root property