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What is the mass of 2.50L of SO2 gas at stp

2 Answers

7 votes

Answer: 4.84 grams

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass, occupies 22.4 L of volume at STP and contains avogadro's number
6.023* 10^(23) of particles.

To calculate the number of moles, we use the equation:


\text{Number of moles}=\frac{\text{Given volume}}{\text{Molar volume}}=(2.50)/(22.4)=0.11

1 mole of
SO_2 weighs = 44 g

0.11 moles of
SO_2 weigh =
\frac{44}1}* 0.11=4.84g

Thus mass of 2.5 L of
SO_2 weigh 4.84 grams.

User Vin Xi
by
8.2k points
5 votes
STP is abbreviation for Standard Temperature and Pressure at which the temperature is 273 K and pressure is 1 atm
- At these conditions the molar volume is equal to 22.4 L
so 1 mole of SO₂ volume = 22.4 L
? mole of SO₂ volume = 2.5 L
number of moles = 2.5 / 22.4 = 0.1116 mol
mass of SO₂ = 0.1116 * 64.063 = 7.15 g
User Santuxus
by
7.9k points