Question

If the area is 140 5/8 and the height is 11 1/4 what is the base for a parallelogram

Answer 1

the area of a parallelogram is pretty straighforward, A = bh, base * height.

now, let's first off convert those mixed fractions to "improper", and then plug them in,


`\bf \stackrel{mixed}{140(5)/(8)}\implies \cfrac{140\cdot 8+5}{8}\implies \stackrel{improper}{\cfrac{1125}{8}} \\\\\\ \stackrel{mixed}{11(1)/(4)}\implies \cfrac{11\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{45}{4}}\\\\ -------------------------------\\\\`


`\bf \textit{area of a parallelogram}\\\\ A=bh\qquad \begin{cases} A=(1125)/(8)\\\\ h=(45)/(4) \end{cases}\implies \cfrac{1125}{8}=b\left( \cfrac{45}{4} \right)\implies \cfrac{\quad(1125)/(8) \quad }{(45)/(4)}=b \\\\\\ \cfrac{1125}{8}\cdot \cfrac{4}{45}=b\implies \cfrac{25}{2}\cdot \cfrac{1}{1}=b\implies \cfrac{25}{2}=b\implies 12(1)/(2)=b`