Question

Please help! This is due tomorrow!

A cyclist maintains a constant velocity of 6.4 m/s headed away from point A. At some initial time, the cyclist is 249 m from point A.
Part A: What will be his displacement from his starting position after 79 s?
Part B: What will be his position from point A after that time?

Answer 1

v = 5.5 m/s
d = 259 m

where v is velocity and d is displacement

Let us first find the displacement after 54 s.

d = vt

d = (5.5 m/s)(54 s)
d = 297 m

Lets find his position from point A after that time.

We take the difference between the displacement at initial time and 54 seconds.

297 m - 259 m = 38m

His position from point A after that time is 38m