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If g(x) = x3 - 5 and h(x) = 2x - 2, then h(g(-2))= ?

User Brodrigues
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2 Answers

5 votes

Answer:

-28

Explanation:

usatestprep

User Zoka
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Please, write "x^3" for "the cube of x," not "x3." "^" denotes exponentiation.

Then you have g(x) = x^3 - 5 and (I assume) h(x) = 2x - 2.

1) evaluate g(x) at x = -2: g(-2) = (-2)^3 - 5 = -8 - 5 = -13

2) let the input to h(x) be -13: h(-13) = 2(-13) - 2 = -28 (answer)
User Sasgorilla
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