Question

given that the center of a circle is at point (-3,5) and that the radius of the circle is 6 units, write the the equation of the circle

Answer 1

The equation of a cricle is

`(x-h)^(2)+(y-k)^(2)=r^(2)`
h being the x coordinate of the given point and k being the y coordinate of the given point (r also being the radius).

Now we have to plug the points into the equation

`(x--3)^(2) +(y-5)^(2) = 6^(2)`
now just simplify the the equation

`(x+3)^(2) +(y-5)^(2) = 36`