Question

the specific heat of water is 4.2 j/c. if it takes 31,500 joules to heat to warm 750 g of water, what was the temperature change?

Answer 1

The amount of heat needed to increase the temperature of a substance by
`\Delta T` is given by

`Q=mC_s \Delta T`
where
m is the mass of the substance

`C_s` the specific heat capacity

`\Delta T` the increase in temperature

In our problem, the mass of the water is m=750 g, the specific heat is
`C_s = 4.2 J/g ^(\circ)C` and the amount of heat supplied is
`Q=31500 J`, so if we re-arrange the previous formula we find the increase in temperature of the water:

`\Delta T= (Q)/(m C_s)= (31500 J)/((750 g)(4.20 J/g^(\circ) C))=10^(\circ)C`