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The equation (x+7)(x-1)=-16 has a. two real solutions b. one real solution c. two complex solutions d. no solution

The equation (x+7)(x-1)=-16 has a. two real solutions b. one real solution c. two complex solutions d. no solution
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the equation (x+7)(x-1)=-16 has a. two real solutions b. one real solution c. two complex solutions d. no solution

User Gosha
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4 votes
here’s my answer! Hope it makes sense :)
the equation (x+7)(x-1)=-16 has a. two real solutions b. one real solution c. two-example-1
User Darren Corbett
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(x+7)(x-1) = -16

x² + 6x - 7 = -16

x² + 6x - 7 + 16 = 0

x² + 6x + 9 = 0

(x+3)² = 0

x = - 3 -> one real solution
User Christophor
by
8.6k points
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