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Calculate the volume of oxygen required to burn 12.00 l of ethane gas, c2h6, to produce carbon dioxide and water, if the volumes of c2h6 and o2 are measured under the same conditions of temperature and pressure

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The volume of oxygen required to burn 12.00 L ethane is calculated as follows

find the moles of C2H6 used

At STP 1 mole is always = 22.4 L, what about 12.00 L

= ( 12.00L x 1 moles) 22.4 L = 0.536 moles

write the reacting equation

2C2H6+ 7O2 = 4CO2 + 6H2O
by use of mole ratio between C2H6 :O2 which is 2:7 the moles of O2

= 0.536 x7/2= 1.876 moles

again at STP 1mole = 22.4 L what about 1.876 moles

= 22.4 L x 1.876 moles/ 1 mole = 42.02 L


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