Question

Three hundred grams of aluminum are heated from −50 ◦c to 300 ◦c. if the specific heat of aluminum is 0.88 j/(g ◦c), what is the change in entropy of the aluminum?

Answer 1

Q = mCΔT
Q is heat in Joules, m is mass, C is specific heat, and ΔT is change in temp

Q = (300g)(.88)(350 degrees) = 92400 J or 92.4 kJ