Question

Explain how you would prepare a solution of sucrose with a molarity of 0.25.

Answer 1

Solution of 0.25 M is prepared in two steps,

1) Calculate Amount of Solute:

Molar Mass of Solute: 342.3 g/mol

As we know,
Molarity = Moles / 1 dm³
or,
Moles = Molarity × 1 dm³
Putting Values,
Moles = 0.25 mol.dm⁻³ × 1 dm³

Moles = 0.25 moles

Now, find out mass of sucrose,
As,
Moles = Mass / M.mass
or,
Mass = Moles × M.mass
Putting Values,
Mass = 0.25 mol × 342.3 g.mol⁻¹

Mass = 85.57 g

2) Prepare Solution:
Take Volumetric flask and add 85.57 g of sucrose in it. Then add distilled water up to the mark of 1 dm³. Shake well! The solution prepared is 0.25 M in 1 Liter.