Question

The lengths of the sides of triangle XYZ are in terms of the variable m , where 

m  ≥ 6. Which is correct regarding the angles of the triangle?
mX < mZ < mY
mY < mZ < mX
mY < mX < mZ
mZ < mY < mX


I think its c but im not sure

Answer 1

Answer: mY < mZ < mX

Explanation:

Given: The lengths of the sides of triangle XYZ are in terms of the variable m, where m ≥ 6.

Let m =6 the least value for m , then

`XZ=m-3=6-3=3`

`XY=m+8=6+8=14`

`ZY= 2m+3=2(6)+3=12+3=15`

We can see
`XZ<XY<ZY`

Since the angle apposite to the larger side of a triangle is larger.

Therefore, mY < mZ < mX

Answer 2

mY < mZ < mX

Explanation:

Since we know that m≥6, we will substitute 6 in for m.

This makes XZ = m-3 = 6-3 = 3. XY = m+8 = 6+8 = 14. YZ = 2(6)+3 = 12+3 = 15.

This makes the sides, in order from least to greatest, XZ < XY < YZ.

The angles associated with these are opposite their corresponding sides; XZ corresponds with Y; XY corresponds with Z; and YZ corresponds with X. This means our inequality would be

Y < Z < X