Question

The base of the parallelogram, b, can be found by dividing the area by the height.

If the area of the parallelogram is represented by 6x2 + x + 3 and the height is 3x, which represents b, the length of the base?

Answer 1

b =
`2x+(1)/(3)+(1)/(x)`

Explanation:

The area of the parallelogram is represented by
`6x^(2) +x+3`

The height is
`3x`

The base of the parallelogram, b, can be found by dividing the area by the height.

So, 'b' can be found as
`(6x^(2)+x+3 )/(3x)`

In simplified form, we can write this as :

=>
`(6x^(2) )/(3x)+(x)/(3x)+ (3)/(3x)`

=>
`2x+(1)/(3)+(1)/(x)`

Hence, base or 'b' is
`2x+(1)/(3)+(1)/(x)`

Answer 2

The area of a parallelogram is:
A = b * h
Where,
b: base
h: height
Clearing the base we have:
b = A / h
Substituting values we have:
b = (6x2 + x + 3) / 3x
Rewriting we have:
b = 2x + 1 / x + 1/3
Answer:
the length of the base is:
b = 2x + 1 / x + 1/3