Question

An astronaut on the planet Trappist-1b tosses a rock horizontally with a speed of 7.95m/s. The rock falls through a vertical distance of 2.35m and lands horizontal distance of 9.57m from the astronaut. What is the acceleration of gravity on Trappist-1b ?

Answer 1

In this case, there are two displacements: Dx and Dy

Dy = 2.35 m
Dx = 9.57 m
Vx = 7.95 m/s

Now, Dx = Vxt => t= Dx/Vx = 9.57/7.95 = 1.204 seconds

Then,

Dy = Vit+1/2gt^2 => g = (Dy-Viyt)*2/t^2 = (2.35-0)*2/1.204^2 = 3.242 m/s^2

Therefore,
Gravitational acceleration = 3.242 m/s^2