Question

What are the solutions to the quadratic equation x^2-16=0

Answer 1

Simplifying this, we get:
(x+4)(x-4) = 0
Now, to get 0, we can replace x for one of these things to make 0, so:
x can either be 4, or -4

Answer 2

Solution of the quadratic equation
`x^(2)-16=0` is 4 and -4.

Explanation:

The given quadratic equation is
`x^(2)-16=0`

To find the solutions of the quadratic equation, we first need to make the factors of
`x^(2)-16`.

We know that we can write
`a^(2) -b^(2) =(a-b)(a+b)`

So,
`x^(2) -16` can be written as
`x^(2) -4^(2)`, and it can be further written as
`(x-4)(x+4)`.

Now, on solving
`x^(2)-16=0` we have,

`x^(2)-16=0`

`x^(2) -4^(2)=0`

`(x-4)(x+4)=0`

So, either
`x-4=0` or
`x+4=0`

`x=4` or
`x=-4`

Hence, the solution of the quadratic equation
`x^(2)-16=0` is 4 and -4.