Question

A set of data follows a nonstandard normal distribution curve. Find the probability that a randomly selected value will be between 660 and 680 given a mean of 715 and a standard deviation of 24.

A.
0.0611

B.
0.7100

C.
0.8300

D.
0.9169

Answer 1

The probability that a randomly selected value will be between 660 and 680 is 0.0614

Explanation:

we are given

mean=715

`\mu=715`

standard deviation =24

`\sigma=24`

At x=660:

`z=(x-\mu)/(\sigma)`

now, we can plug values

`z=(660-715)/(24)`

`z=-2.29167`

At x=680:

`z=(x-\mu)/(\sigma)`

now, we can plug values

`z=(680-715)/(24)`

`z=-1.45833`

now, we can find probability

`P(-2.29167\leq z\leq -1.45833)`

we can use table

and we get

`P(-2.29167\leq z\leq -1.45833)=0.0614`