Question

Write the equilibrium constant formula for the following reaction: 2H2+O2 yields 2H2O

Answer 1

`2 H_(2) + O_(2) ---\ \textgreater \ 2H_(2)O`


`K= ( [H_(2)O]^(2) )/( [H_(2)]^(2) [O_(2)])`

Answer 2

The expression for an equilibrium constant for the given reaction:

`K_c=([H_2O]^2)/([H_2]^2[O_2)}`

Step-by-step explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as
`K_(eq)`

K is the constant of a certain reaction when it is in equilibrium, while Q is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

For the given chemical reaction:

`2H_2+O_2\rightleftharpoons 2H_2O`

The expression for an equilibrium constant will be given by:

`K_c=([H_2O]^2)/([H_2]^2[O_2)}`