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If a gas with a volume of 12.5 L was cooled from 18 C to 0 C at constant pressure. What is the final volume

User Meral
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We can solve the problem by using Charle's law, which states that for a transformation of an ideal gas at constant pressure, the ratio between volume and absolute temperature of the gas remains constant:

(V)/(T)=k
where V is the volume of the gas and T its absolute temperature.

The previous law can be rewritten as

(V_1)/(T_1)= (V_2)/(T_2) (1)
Let's convert the initial and final temperatures of the gas in Kelvin:

T_1=18C+273=291 K

T_2 = 0C+273 = 273 K
and the intiial volume is

V_1 = 12.5 L

so if we re-arrange equation (1) and we use these data, we can find the final volume of the gas:

V_2=V_1 (T_2)/(T_1)=(12.5 L) (273 K)/(291 K)=11.7 L
User Kimkunjj
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