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Write (3i-2/3) - (6i-5) as a complex number in standard form
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Write (3i-2/3) - (6i-5) as a complex number in standard form

User Nyah
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The correct answer is B. 13/3 - 3i
User Vibha Chosla
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The standard form of a complex number is: a+bi
thus evaluating the expression we get:
(3i-2/3)-(6i-5)
opening the parenthesis we get:
3i-2/3-6i+5
=(3i-6i)-2/3+5
=-3i+13/3
thus the standard form will be:
13/3-3i
multiplying through by 3 we get:
13-9i
User Dmjy
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