Question

How many protons z and how many neutrons n are there in a nucleus of the most common isotope of silicon, 2814si? separate your answ?

Answer 1

The Atomic Number and Atomic Mass of ²⁸Si₁₄ are 14 and 28 respectively.

Atomic Number:
Atomic Number of Element is the Number of Protons contained by the Element. So, there are 14 Protons in ²⁸Si₁₄.

Atomic Mass:
Atomic Mass of Element is the total number of Protons and Neutrons present in the Nucleus of that element.
So,
Atomic Mass = # of Protons + # of Neutrons

As the Atomic mass of ²⁸Si₁₄ is 28 and it has 14 protons, So # of Neutrons are calculated as,

# of Neutrons = Atomic Mass - # of Protons

# of Neutrons = 28 - 14

# of Neutrons = 14

Result:
In ²⁸Si₁₄ Number of Neutrons are 14, Number of Protons are 14.

Z = 14 , n = 14