Question

What is the vertex of the parabola? y+1=−14(x−2)2 enter your answer in the boxes?

Answer 1

y + 1 = -14(x - 2)^2
y = -14(x - 2)^2 - 1
The vertex is the point (h, k) when the parabola is in the turning point form: y = a(x - h)^2 + k, therefor the vertex is at (2, -1)

Answer 2

Vertex ( h,k) : ( 2 ,-1) .

Explanation:

Given : y+1=−14(x−2)².

To find : What is the vertex of the parabola?

Solution : We have given that y+1=−14(x−2)².

Vertex form of parabola: y=a(x−h)²+k.

Where , ( h ,k ) are vertex

we have y+1=−14(x−2)²

On subtracting by both sides

y = −14(x−2)² - 1

On comparing with Vertex form of parabola

a = - 14 ; h = 2 ; k = -1.

Therefore, Vertex ( h,k) : ( 2 ,-1) .