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What are the zeros of the function f(x)=x^2+x-20?

2 Answers

4 votes

-5 and 4

those are the correct answers

User BPX
by
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5 votes

Answer:

The zeroes of the given function are -5 and 4.

Explanation:

The given function is


f(x)=x^2+x-20

Equate the given function equal to 0, to find the zeroes of the given function.


x^2+x-20=0

Write the middle term as 5x-4x.


x^2+5x-4x-20=0


(x^2+5x)+(-4x-20)=0

Taking out common factors from each parenthesis.


x(x+5)-4(x+5)=0


(x-4)(x+5)=0

Using zero product property, we get


x-4=0\Rightarrow x=4


x+5=0\Rightarrow x=-5

Therefore the zeroes of the given function are -5 and 4.

User Amit Teli
by
8.0k points