Question

The product of two consecutive even integers is 840 find these numbers

Answer 1

Integers are 2n and 2n +2
2n * (2n + 2) = 840
4n^2 + 4n -840 = 0
Solving by quadratic formula:
n = 14 and n+2 = 16
Therefore the integers (2*n and 2*n+2) are
28 and 30

check:
28 * 30 = 840