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The allele for unattached earlobes is dominant over the allele for attached earlobes. in a population of 500 individuals, 25 percent show the recessive phenotype. how many individuals would you expect to be homozygous dominant and heterozygous for this trait

User Slouc
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1 Answer

6 votes
Equation:

p^2+q^2=1.0 p^2+2pq+q^2=1.0

q^2=.25
p^2+.25=1.0
p^2=.75
.75 x 500

p^2 =375 are homozygous dominant

square root of .75 = .87
square root of .25 =.5
2(.87)(.5)
.87 .87 X 500 =435 are heterozygous


User Fathi
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