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Find f ′(x) for f(x) = sin (3x2).
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Find f ′(x) for f(x) = sin (3x2).

User Rahul Shukla
by
8.9k points

1 Answer

4 votes

Answer:

f'(x) = cos(3x^2)(6x)

Explanation:

(d/dx)(sin u) = cos(u)·du/dx . . . . . chain rule

For f(x) = sin(3x^2), this means ...

f'(x) = cos(3x^2)(6x)

User Jtesch
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