Question

Matt forgot to put the fabric softener in the wash. As his socks tumbled in the dryer, they became charged. If a small piece of lint with a charge of +1.25 E -19 C is attracted to the socks by a force of 3.0 E -9 N, what is the magnitude of the electric field at this location?

Answer 1

`2.4\cdot 10^(10) N/C`

Step-by-step explanation:

The electric force exerted on a charge due to an electric field is given by:

`F=qE`

where

q is the magnitude of the charge

F is the magnitude of the force

E is the magnitude of the electric field

In this problem, we have:

`q=1.25\cdot 10^(-19)C` is the charge

`F=3.0\cdot 10^(-9) N` is the magnitude of the force

using these data and re-arranging the equation, we can calculate the magnitude of the electric field:

`E=(F)/(q)=(3.0\cdot 10^(-9) N)/(1.25\cdot 10^(-19) C)=2.4\cdot 10^(10) N/C`